Beginner C++ help plz?

Write a function that accepts an array of integers and an integer that represents the size of the array. This function will reverse the order of the array. Ex:





if a[0] = 4, a[1] = 2, a[2] = 9, a[3] = 89;





After executing this function:





a[0] = 89, a[1]=9, a[2] = 2, a[3] = 4





#include %26lt;iostream%26gt;


using namespace std;





int main()


{


const int SIZE = 4;


int a[4] = {4, 2, 9, 89};





for (int count = 0; count %26lt; SIZE; count++)


b[count] = a[count];








return 0;


}





I have this so far, I can't get any farther, can u please make some changes.

Beginner C++ help plz?
This is a very very common question especially on job interviews so it is important that you have as an elegant as solution as possible.





void Reverse(int* array, int length)


{


int i, tmp;





for (i=0; i%26lt;len/2; i++)


{


tmp = array[i] ;


array[i] = array[len-i-1] ;


array[len-i-1] = tmp;


}





note there is an even more elegant solution using the ^ (xor) operation but that is not for the beginner.





**** Note I edited the second line from


array[i] = tmp


to


array[len-i-1]


}
Reply:What do you need to do here honey? What does b[count]=a[count] do ? It makes and exact copy of the array, right?


Whare you want to do is flip the array. You want that line to be something like this:


b[count]=a[SIZE-count];


This may look wrong at first, but try it out, you will be plesantly surprised.


Do the math for it and you will see what is happening.


b[0]=b[4-0]


b[1]=b[4-1]


and so on....





:)





Actually I also like the other guys answer for this one, that is a much more elegant solution.